{ "cells": [ { "cell_type": "markdown", "id": "markdown-000", "metadata": {}, "source": [ "# Solving motion with initial conditions\n", "\n", "[Read the lesson](https://tirta.co/a-byte-of-physics/solving-motion-initial-conditions). This notebook includes the lesson text and its Python examples in reading order. Run the setup cell, then run the remaining cells from top to bottom. In Colab, use File → Save a copy in Drive to keep your edits. You can run and edit this view without changing the course source. Examples use illustrative data unless stated otherwise." ] }, { "cell_type": "code", "id": "code-001", "metadata": {}, "source": [ "import importlib.metadata\n", "import subprocess\n", "import sys\n", "\n", "requirements = {\"numpy\": (2, 0), \"sympy\": (1, 13), \"matplotlib\": (3, 8)}\n", "to_install = []\n", "for package, minimum in requirements.items():\n", " try:\n", " installed = importlib.metadata.version(package)\n", " version = tuple(int(part) for part in installed.split(\".\")[:2])\n", " except importlib.metadata.PackageNotFoundError:\n", " version = (0, 0)\n", " if version < minimum:\n", " to_install.append(f\"{package}>={minimum[0]}.{minimum[1]}\")\n", "if to_install:\n", " subprocess.check_call([sys.executable, \"-m\", \"pip\", \"install\", *to_install])\n", "\n", "import numpy as np\n", "import sympy as sp\n", "import matplotlib\n", "import matplotlib.pyplot as plt\n", "\n", "print(\"Python\", sys.version.split()[0])\n", "print(\"NumPy\", np.__version__)\n", "print(\"SymPy\", sp.__version__)\n", "print(\"Matplotlib\", matplotlib.__version__)\n" ], "execution_count": null, "outputs": [] }, { "cell_type": "markdown", "id": "markdown-002", "metadata": {}, "source": [ "A rule for acceleration does not determine one unique motion by itself. The same\n", "acceleration can describe objects that start in different places or with different\n", "velocities. Initial conditions select one trajectory from the family allowed by the\n", "equation.\n", "\n", "## Why a second-order equation needs two values\n", "\n", "In one dimension, acceleration is the second derivative of position:\n", "\n", "\n", "$$\n", "\\frac{\\mathrm{d}^2x}{\\mathrm{d}t^2}=a(t,x,v)\n", "$$\n", "\n", "\n", "Integrating once introduces a constant that is fixed by velocity at an initial time.\n", "Integrating again introduces another constant fixed by position. The initial state is\n", "therefore\n", "\n", "\n", "$$\n", "x(t_0)=x_0,\\qquad v(t_0)=v_0\n", "$$\n", "\n", "\n", "The reference time $t_0$ is part of the\n", "definition. Setting it to zero is convenient but not required.\n", "\n", "For constant acceleration, integration gives\n", "\n", "\n", "$$\n", "v(t)=v_0+a(t-t_0)\n", "$$\n", "\n", "\n", "and\n", "\n", "\n", "$$\n", "x(t)=x_0+v_0(t-t_0)+\\frac{1}{2}a(t-t_0)^2\n", "$$\n", "\n", "\n", "Writing elapsed time as $t-t_0$\n", "prevents a clock reading from being mistaken for the duration of motion.\n", "\n", "## Translate the state explicitly" ] }, { "cell_type": "code", "id": "code-003", "metadata": {}, "source": [ "from dataclasses import dataclass\n", "\n", "\n", "@dataclass(frozen=True)\n", "class MotionState:\n", " time_seconds: float\n", " position_metres: float\n", " velocity_metres_per_second: float\n", "\n", "\n", "def state_at_constant_acceleration(\n", " initial: MotionState,\n", " acceleration_metres_per_second_squared: float,\n", " requested_time_seconds: float,\n", ") -> MotionState:\n", " elapsed_time_seconds = requested_time_seconds - initial.time_seconds\n", "\n", " velocity_metres_per_second = (\n", " initial.velocity_metres_per_second\n", " + acceleration_metres_per_second_squared * elapsed_time_seconds\n", " )\n", "\n", " position_metres = (\n", " initial.position_metres\n", " + initial.velocity_metres_per_second * elapsed_time_seconds\n", " + 0.5 * acceleration_metres_per_second_squared * elapsed_time_seconds**2\n", " )\n", "\n", " return MotionState(\n", " time_seconds=requested_time_seconds,\n", " position_metres=position_metres,\n", " velocity_metres_per_second=velocity_metres_per_second,\n", " )\n" ], "execution_count": null, "outputs": [] }, { "cell_type": "markdown", "id": "markdown-004", "metadata": {}, "source": [ "The returned position and velocity are derived values. The function should not mutate\n", "the supplied initial record; later evaluations must continue to refer to the same\n", "initial event.\n", "\n", "The corresponding Python keeps each physical step visible:" ] }, { "cell_type": "code", "id": "code-005", "metadata": {}, "source": [ "initial = MotionState(\n", " time_seconds=1.0,\n", " position_metres=2.0,\n", " velocity_metres_per_second=3.0,\n", ")\n", "result = state_at_constant_acceleration(initial, 0.5, 5.0)\n", "print(result)\n", "assert result.position_metres == 18.0\n", "assert result.velocity_metres_per_second == 5.0\n" ], "execution_count": null, "outputs": [] }, { "cell_type": "markdown", "id": "markdown-006", "metadata": {}, "source": [ "## A braking example\n", "\n", "At clock time $t_0=3.0\\,\\mathrm{s}$,\n", "a cart is at $x_0=5.0\\,\\mathrm{m}$\n", "and moving right at\n", "$v_0=12.0\\,\\mathrm{m/s}$.\n", "It then has constant acceleration\n", "$a=-2.0\\,\\mathrm{m/s^2}$.\n", "\n", "At clock time $t=7.0\\,\\mathrm{s}$,\n", "the elapsed time is $4.0\\,\\mathrm{s}$.\n", "The velocity is\n", "\n", "\n", "$$\n", "v=12.0+(-2.0)(4.0)=4.0\\,\\mathrm{m/s}\n", "$$\n", "\n", "\n", "and the position is\n", "\n", "\n", "$$\n", "x=5.0+(12.0)(4.0)+\\frac{1}{2}(-2.0)(4.0)^2=37.0\\,\\mathrm{m}\n", "$$\n", "\n", "\n", "The negative acceleration reduces a positive velocity, so the cart is slowing during\n", "this interval. Negative acceleration alone does not mean motion in the negative\n", "direction.\n", "\n", "## Solve for an event from the same initial state\n", "\n", "The cart reaches zero velocity when\n", "\n", "\n", "$$\n", "0=v_0+a\\Delta t\\quad\\Rightarrow\\quad\\Delta t=-\\frac{v_0}{a}=6.0\\,\\mathrm{s}\n", "$$\n", "\n", "\n", "Its stopping position is\n", "\n", "\n", "$$\n", "x_{\\mathrm{stop}}=5.0+(12.0)(6.0)+\\frac{1}{2}(-2.0)(6.0)^2=41.0\\,\\mathrm{m}\n", "$$\n", "\n", "\n", "If the constant-acceleration formula is evaluated after that event, it predicts negative\n", "velocity and motion back to the left. That is mathematically correct for constant\n", "negative acceleration, but it may not represent a real braking system that stops\n", "applying force once the cart rests. Initial conditions do not specify future control\n", "changes; the model needs a piecewise force or acceleration rule for that behavior.\n", "\n", "## Initial conditions and parameters differ\n", "\n", "Initial position and velocity describe the selected trajectory at one event. Parameters\n", "such as a drag coefficient or spring stiffness describe the model's rule. Constant\n", "acceleration is a parameter in the closed-form example, although a more general solver\n", "might compute acceleration from state and parameters.\n", "\n", "Changing the initial position shifts the trajectory without changing its velocity or\n", "acceleration. Changing the initial velocity changes both the position slope and future\n", "velocity. Changing acceleration changes the rule itself. Keeping these categories\n", "separate helps parameter sweeps and uncertainty analyses say what was varied.\n", "\n", "## Numerical initial-value problems\n", "\n", "For state-dependent acceleration, the equations can be rewritten as two first-order\n", "equations:\n", "\n", "\n", "$$\n", "\\frac{\\mathrm{d}x}{\\mathrm{d}t}=v,\\qquad\\frac{\\mathrm{d}v}{\\mathrm{d}t}=a(t,x,v)\n", "$$\n", "\n", "\n", "A numerical integrator begins with the complete initial state and advances it. Omitting\n", "initial velocity leaves the first update underdetermined. Guessing zero is an extra\n", "assumption that must be explicit." ] }, { "cell_type": "code", "id": "code-007", "metadata": {}, "source": [ "time_s, position_m, velocity_m_per_s = 1.0, 2.0, 3.0\n", "dt_s = 0.01\n", "for step in range(400):\n", " acceleration = 0.5\n", " position_m += velocity_m_per_s * dt_s\n", " velocity_m_per_s += acceleration * dt_s\n", " time_s += dt_s\n", "print(f\"Numerical position: {position_m:.3f} m\")\n", "print(f\"Numerical velocity: {velocity_m_per_s:.3f} m/s\")\n" ], "execution_count": null, "outputs": [] }, { "cell_type": "markdown", "id": "markdown-008", "metadata": {}, "source": [ "The step size and integrator determine numerical error. The initial-state uncertainty\n", "also propagates through the trajectory, and in sensitive systems nearby initial states\n", "may diverge rapidly.\n", "\n", "## Initial conditions are not boundary conditions\n", "\n", "An initial-value problem supplies all required state at one time and predicts evolution.\n", "A boundary-value problem may specify information at different positions or times, such\n", "as the endpoints of a hanging cable. Solving it often requires finding an initial state\n", "that satisfies the later boundary.\n", "\n", "The distinction matters in code. Passing an endpoint target to an initial-value\n", "integrator does not guarantee that the trajectory reaches it. A shooting method, root\n", "finder, or other boundary-value algorithm may be needed.\n", "\n", "## Checks tied to the initial event\n", "\n", "Every solver should reproduce its initial state at the initial time. For the analytic\n", "function, substituting $t=t_0$\n", "must return $x=x_0$\n", "and $v=v_0$.\n", "\n", "Additional checks include dimensional consistency, comparison of derivatives, known\n", "event times, and invariance under a shift of clock origin. Adding the same constant to\n", "both initial and requested clock times must leave the predicted position and velocity\n", "unchanged because elapsed time is unchanged.\n", "\n", "Finally, state the domain. A function can numerically extrapolate before the initial\n", "event or beyond a collision, control change, or model limit. Being able to compute a\n", "number does not make that number a supported physical prediction.\n", "\n", "## Measured initial conditions carry uncertainty\n", "\n", "In an experiment, the initial state is not normally known as an exact pair of numbers.\n", "Position may be limited by image resolution, velocity may be estimated from several\n", "frames, and the two estimates may be correlated. Starting a solver from only their\n", "central values produces one representative trajectory but does not show how uncertainty\n", "spreads through later predictions.\n", "\n", "One approach is to sample plausible initial states from a stated joint distribution and\n", "solve the same model for each sample. Another is to propagate a covariance matrix with a\n", "linearized model. Either approach must preserve units, correlations, and the time at\n", "which the measurements define the state. Treating position measured at one instant and\n", "velocity measured over a later interval as simultaneous can introduce a hidden timing\n", "error.\n", "\n", "For stable linear motion, nearby initial states remain predictably related. In nonlinear\n", "or chaotic systems, small differences may grow quickly. That growth is a property of the\n", "model's dynamics and time horizon; it is not fixed by printing more digits in the initial\n", "record. Report the initial uncertainty and sensitivity beside the later prediction.\n", "\n", "## Choose enough state, but no more than needed\n", "\n", "State must contain the information required to continue the model. For a particle whose\n", "acceleration depends on position and velocity, both are needed. Storing acceleration as\n", "independent state is unnecessary when it can be calculated from current time, position,\n", "velocity, and parameters. Duplicating derived values creates opportunities for them to\n", "become inconsistent.\n", "\n", "Some models require more state. A force with memory may need internal material\n", "variables; a controller may need its own mode and accumulated error; a rocket may need\n", "changing mass. The order of the differential equations indicates how many independent\n", "conditions are required, while the physical model determines what those conditions\n", "mean.\n", "\n", "Do not add a state variable merely because it is convenient to display. Outputs such as\n", "kinetic energy can be derived from the current physical state. Keep display rounding out\n", "of state as well, so each update begins from the best available internal values.\n", "\n", "## Rebase an initial state safely\n", "\n", "Sometimes a long trajectory is restarted from a later computed event. The new initial\n", "record must copy position and velocity from the same time and preserve model parameters\n", "and units. If the earlier state is numerical, the restart also inherits its accumulated\n", "error. It is not equivalent to receiving a new exact measurement.\n", "\n", "A useful check evaluates the original solution and the rebased solution at matching\n", "later times. For a time-invariant constant-acceleration model, they should agree within\n", "floating-point tolerance. Disagreement can reveal a clock-origin error, lost state, or\n", "incorrect use of elapsed time.\n", "\n", "## A worked Python notebook\n", "\n", "Start from a position of 2 metres and velocity of 3 metres per second, then accelerate uniformly. The question for this calculation is precise: how does **position**\n", "change when we change **elapsed time**, while keeping the other choices fixed?\n", "The earlier sections explain the physical relationship. Here we turn one part of that\n", "relationship into a calculation that you can run, inspect, and change in Google Colab.\n", "\n", "Elapsed time is measured from the specified initial event, not from an arbitrary clock origin. Keep that sentence beside the results. A formula can return a number outside\n", "its useful range, and a plotting library will usually draw that number without asking\n", "whether the physical assumptions still hold. The selected interval is from\n", "0 to 4 s. It gives us a specific domain to discuss\n", "instead of leaving the graph's range to a software default.\n", "\n", "Use the notebook link above the lesson, run the setup cell, and then run the cells in\n", "order. The code below is also included there. NumPy handles the arrays of numerical\n", "values, SymPy keeps the equation symbolic, and Matplotlib draws the results. If these\n", "libraries or notebook cells are unfamiliar, start with\n", "[Your first physics notebook](https://tirta.co/a-byte-of-physics/your-first-physics-notebook).\n", "\n", "### State the relationship before choosing a graph\n", "\n", "In this small example, `q` stands for elapsed time, expressed in s. The output is\n", "position, expressed in m. The equation below uses the numerical values in those\n", "units. Any fixed coefficients therefore carry the units needed to make the relation\n", "consistent. A value supplied in another unit must be converted before it enters this\n", "expression.\n", "\n", "\n", "$$\n", "f(q) = \\frac{q^{2}}{4} + 3 q + 2\n", "$$\n", "\n", "\n", "This is a function of one changing input. It is not a statement that the physical\n", "system has only one variable. We deliberately hold the other inputs fixed so that one\n", "cause of variation is visible. Changing several inputs at once would make it harder\n", "to tell which change produced the output difference. Write down the held-fixed choices\n", "before trying a different experiment.\n", "\n", "At 2 s, the expression gives 9 m. This is our\n", "reference calculation. It is a prediction of the stated example, not a new measurement.\n", "Its displayed digits help us compare implementations. They should not be read as a\n", "claim that physical inputs are known to six significant figures." ] }, { "cell_type": "code", "id": "code-009", "metadata": {}, "source": [ "import numpy as np\n", "import sympy as sp\n", "import matplotlib.pyplot as plt\n", "\n", "q = sp.Symbol(\"q\", real=True)\n", "expression = sp.sympify(\"2+3*q+q**2/4\", locals={\"q\": q})\n", "reference_input = 2.0\n", "reference_output = float(expression.subs(q, reference_input))\n", "print(\"Input:\", reference_input, \"s\")\n", "print(\"Predicted position:\", reference_output, \"m\")\n" ], "execution_count": null, "outputs": [] }, { "cell_type": "markdown", "id": "markdown-010", "metadata": {}, "source": [ "`sp.Symbol` declares a mathematical symbol. It does not assign a numerical measurement\n", "to that symbol. `subs` then replaces the symbol with our chosen input, and `float`\n", "converts the resulting symbolic number into a standard Python numerical value.\n", "Keeping these steps separate lets us inspect the equation before numerical substitution.\n", "It also prevents a later plot from becoming the only surviving record of the model.\n", "\n", "### Compare a few cases you can explain\n", "\n", "Before drawing hundreds of points, calculate three. The lower endpoint gives\n", "2 m. The midpoint, at 2 s, gives\n", "9 m. The upper endpoint gives 18 m.\n", "Read these together with the assumptions: they describe different choices of elapsed time\n", "within the same example, with the other inputs held fixed.\n", "\n", "These three values are a useful first check, but they do not establish the shape between\n", "them. Two endpoints can be equal even when the curve bends or oscillates in between.\n", "Likewise, a large change between endpoints does not tell us whether the relationship is\n", "linear. We need the equation and intermediate samples to answer those questions." ] }, { "cell_type": "code", "id": "code-011", "metadata": {}, "source": [ "evaluate = sp.lambdify(q, expression, modules=\"numpy\")\n", "inputs = np.array([0.0, 2.0, 4.0])\n", "outputs = np.asarray(evaluate(inputs), dtype=float)\n", "outputs = np.broadcast_to(outputs, inputs.shape)\n", "for input_value, output_value in zip(inputs, outputs):\n", " print(f\"{input_value:.6g} s -> {output_value:.6g} m\")\n", "assert np.all(np.isfinite(outputs))\n" ], "execution_count": null, "outputs": [] }, { "cell_type": "markdown", "id": "markdown-012", "metadata": {}, "source": [ "`lambdify` turns the symbolic expression into a numerical function. We explicitly select\n", "NumPy as its numerical backend so it can accept an array. The same expression now has\n", "two useful forms: one for algebra and one for calculating many cases. The assertion\n", "checks that the chosen inputs produce finite outputs. It would catch an infinity or an\n", "undefined numerical result, but a finite value can still be physically inappropriate.\n", "\n", "### Make a graph that answers the question\n", "\n", "The horizontal axis shows elapsed time; the vertical axis shows position. Every plotted\n", "point is a prediction of the same expression. We mark the reference case separately\n", "so that a reader can connect the earlier printed value to its place on the curve.\n", "The axis labels include units because a shape without a scale cannot tell us the size\n", "of a physical effect." ] }, { "cell_type": "code", "id": "code-013", "metadata": {}, "source": [ "input_grid = np.linspace(0.0, 4.0, 301)\n", "output_grid = np.asarray(evaluate(input_grid), dtype=float)\n", "output_grid = np.broadcast_to(output_grid, input_grid.shape)\n", "fig, ax = plt.subplots(figsize=(7, 4))\n", "ax.plot(input_grid, output_grid, label=\"Stated model\")\n", "ax.scatter([reference_input], [reference_output], label=\"Reference case\", zorder=3)\n", "ax.set_xlabel(\"Elapsed time (s)\")\n", "ax.set_ylabel(\"Position (m)\")\n", "ax.legend()\n", "ax.grid(alpha=0.25)\n", "fig.tight_layout()\n", "plt.show()\n" ], "execution_count": null, "outputs": [] }, { "cell_type": "markdown", "id": "markdown-014", "metadata": {}, "source": [ "Look for a sign change, a turning point, or a region where the curve becomes steep.\n", "Connect each feature to the expression rather than to the colour of the line. If the\n", "curve has a minimum or maximum, changing the input in opposite directions may have\n", "similar effects on the output near that point. If it is nearly straight over a short\n", "interval, a local linear approximation may be useful even when the complete expression\n", "is nonlinear.\n", "\n", "Increasing the number of samples makes the line smoother and may reveal features that\n", "a coarse grid missed. It does not improve the physical inputs or enlarge the model's\n", "validity range. For quantities that can take only discrete values, use the line as a\n", "guide to the relationship and interpret only the allowed input values. A plotting\n", "function does not enforce such restrictions for you.\n", "\n", "### Measure the local sensitivity\n", "\n", "A derivative asks a more specific question than the whole graph: how quickly does\n", "position change near the reference input? Its units are the output unit divided by\n", "the input unit. For this calculation, the derivative at 2 s is\n", "4 in those ratio units. Locally, the output increases as the\n", "input increases. This statement is local; the sign or size of the slope can be different\n", "elsewhere on the curve.\n", "\n", "\n", "$$\n", "f'(q) = \\frac{q}{2} + 3\n", "$$\n", "\n", "\n", "For a small input change, multiply the derivative by that change to estimate the output\n", "change. Then compare that estimate with a fresh evaluation of the full expression.\n", "The distinction between these two calculations matters: the derivative gives a tangent\n", "approximation, while substitution evaluates the chosen expression at the new point." ] }, { "cell_type": "code", "id": "code-015", "metadata": {}, "source": [ "slope_expression = sp.diff(expression, q)\n", "slope_at_reference = float(slope_expression.subs(q, reference_input))\n", "changed_input = 2.02\n", "linear_prediction = reference_output + slope_at_reference * (\n", " changed_input - reference_input\n", ")\n", "full_prediction = float(evaluate(changed_input))\n", "print(\"Symbolic derivative:\", slope_expression)\n", "print(\"Tangent prediction:\", linear_prediction, \"m\")\n", "print(\"Full expression:\", full_prediction, \"m\")\n", "print(\"Approximation difference:\", full_prediction - linear_prediction, \"m\")\n" ], "execution_count": null, "outputs": [] }, { "cell_type": "markdown", "id": "markdown-016", "metadata": {}, "source": [ "Here the changed input is 2.02 s. The tangent estimate is\n", "9.08 m, while the full expression gives\n", "9.0801 m. If the two values are close, it means the chosen\n", "input change is small enough for this local approximation at this point. It does not\n", "mean the entire model is linear. If the slope is zero, a quadratic or higher-order term\n", "may supply the leading change instead.\n", "\n", "This is also the beginning of uncertainty propagation. If the input has a small stated\n", "standard uncertainty, the magnitude of the slope times that uncertainty estimates one\n", "contribution to output uncertainty. Do not automatically use the same rule for a wide\n", "interval, a discontinuity, a turning point with zero first derivative, or several\n", "correlated uncertain inputs. Those situations need more of the model than one slope.\n", "\n", "### Check the derivative with numerical differences\n", "\n", "We can estimate the same slope from values on either side of the reference point.\n", "Subtract the lower output from the upper output and divide by twice the input step.\n", "Parentheses are essential: the entire output difference must be divided by the entire\n", "input interval. Without them, Python can execute a different mathematical expression\n", "while still producing a plausible number.\n", "\n", "The calculation below uses three decreasing step sizes. Each estimate is compared with\n", "the symbolic derivative, so the reference is independent of the numerical difference\n", "formula. Near an endpoint, it is acceptable here to evaluate a small extension only\n", "because the displayed mathematical expression is smooth there; such a check does not\n", "assert that extrapolated values describe additional physical cases." ] }, { "cell_type": "code", "id": "code-017", "metadata": {}, "source": [ "input_span = 4.0\n", "for fraction in [1e-2, 1e-3, 1e-4]:\n", " step = input_span * fraction\n", " upper = float(evaluate(reference_input + step))\n", " lower = float(evaluate(reference_input - step))\n", " numerical_slope = (upper - lower) / (2 * step)\n", " difference = numerical_slope - slope_at_reference\n", " print(f\"step={step:.6g}: slope={numerical_slope:.6g}, difference={difference:.6g}\")\n" ], "execution_count": null, "outputs": [] }, { "cell_type": "markdown", "id": "markdown-018", "metadata": {}, "source": [ "For a smooth function, reducing the step often reduces the approximation error at first.\n", "Very small steps can eventually make subtraction of nearly equal floating-point values\n", "less reliable. Therefore “smaller” is not an unlimited guarantee of “better.” Compare\n", "the observed behaviour over a useful range of steps instead of choosing the smallest\n", "number the computer can represent.\n", "\n", "An absolute slope difference is useful when the expected slope is near zero. A relative\n", "difference would divide by a very small reference and could look enormous even when the\n", "absolute discrepancy is tiny. Away from zero, a relative difference can help compare\n", "quantities with very different scales. The tolerance should reflect the question and\n", "the numerical method, rather than a universal decimal threshold copied into every test.\n", "\n", "### Change the example and preserve the reasoning\n", "\n", "Make one copy of the reference calculation before editing it. Choose a second value of\n", "elapsed time inside the stated interval, predict whether position will rise or fall,\n", "and then evaluate the expression. Place the prediction and the result in a text cell.\n", "If they disagree, identify whether the mistake was in the sign, the unit conversion,\n", "the algebra, or the assumption about how the curve behaves.\n", "\n", "Next choose a shorter plotting interval around the reference point. Compare the local\n", "curve with its tangent approximation. Then widen the interval again. The difference\n", "shows why a useful local estimate need not describe the whole range. Keep the axis\n", "labels and numerical scale visible when comparing the plots; automatic axis limits can\n", "make two different effects appear equally large.\n", "\n", "Finally, return to the physical limit stated at the start: Elapsed time is measured from the specified initial event, not from an arbitrary clock origin. Describe one change\n", "to the setup that would violate that limit. State what new input, equation, or observation\n", "would be needed before trusting an answer in the changed situation. This last step\n", "connects the Python experiment to the physics instead of treating successful execution\n", "as the only criterion for a useful result.\n", "\n", "Before saving, restart the runtime and run all cells in order. A result that depends on\n", "an earlier, now-deleted input cell is not reproducible from the saved notebook. Keep\n", "unrounded values for later calculations, round only the reported output, and label any\n", "new data as measured, assumed, or generated. The graph and printed values should remain\n", "traceable to the same expression and the same choices of inputs.\n", "\n", "### Recover the output change by integrating the slope\n", "\n", "There is another way to check that the expression and its derivative describe the same\n", "relationship. Add up the small output changes predicted by the slope across the chosen\n", "input interval. In the continuous limit, this integral equals the output at the upper\n", "endpoint minus the output at the lower endpoint. The result has units of m:\n", "the input unit in the integration cancels the input unit in the denominator of the slope.\n", "\n", "This statement is about the mathematics of this particular relationship. It does not\n", "assign a new physical meaning to an arbitrary area under a graph. For example, an area\n", "under force versus distance represents work, while an area under a different pair of\n", "quantities may represent something else or have no standard name. Always carry the\n", "axis units through the calculation before naming an integral." ] }, { "cell_type": "code", "id": "code-019", "metadata": {}, "source": [ "slope_function = sp.lambdify(q, slope_expression, modules=\"numpy\")\n", "endpoint_change = float(evaluate(4.0) - evaluate(0.0))\n", "for points in [101, 201, 401]:\n", " grid = np.linspace(0.0, 4.0, points)\n", " slopes = np.asarray(slope_function(grid), dtype=float)\n", " slopes = np.broadcast_to(slopes, grid.shape)\n", " integrated_change = np.trapezoid(slopes, grid)\n", " print(\n", " points,\n", " \"integrated change:\",\n", " integrated_change,\n", " \"endpoint change:\",\n", " endpoint_change,\n", " )\n" ], "execution_count": null, "outputs": [] }, { "cell_type": "markdown", "id": "markdown-020", "metadata": {}, "source": [ "The trapezoidal rule joins neighbouring slope samples with straight segments and adds\n", "their signed areas. A negative contribution remains negative; replacing every slope\n", "by its magnitude would calculate a different quantity. Increasing the sample count\n", "provides a practical refinement check. If the values do not settle toward the endpoint\n", "difference, first inspect the interval, singularities, and array ordering.\n", "\n", "Do not conclude that two agreeing calculations prove the model is physically complete.\n", "Both use the same selected relationship, so an omitted effect would be omitted from\n", "both. Their agreement is evidence that the numerical tools implement that relationship\n", "consistently. Comparing with an independent experiment or a more appropriate physical\n", "model is a separate test.\n", "\n", "Keep this comparison in the notebook when you change the expression. It is particularly\n", "useful after adding a coefficient, changing a sign convention, or converting an input\n", "unit. A code cell that produces a smooth graph can conceal these mistakes; a second\n", "calculation of the same output change gives you another place to notice them.\n", "\n", "## Sources\n", "- [OpenStax, *University Physics Volume 1*, Section 3.4, \"Motion with Constant Acceleration\"](https://openstax.org/books/university-physics-volume-1/pages/3-4-motion-with-constant-acceleration).\n", "- [MIT OpenCourseWare, *8.01SC Classical Mechanics*, Chapter 4, \"One Dimensional Kinematics\"](https://ocw.mit.edu/courses/8-01sc-classical-mechanics-fall-2016/resources/mit8_01scs22_chapter4/).\n", "- [Benjamin Crowell, *Light and Matter*, Section 3.6, \"Algebraic Results for Constant Acceleration\"](https://open.umn.edu/opentextbooks/textbooks/light-and-matter).\n", "- [The Physics Hypertextbook, \"Kinematic Equations\"](https://physics.info/motion-equations/)." ] } ], "metadata": { "kernelspec": { "display_name": "Python 3", "language": "python", "name": "python3" }, "language_info": { "name": "python", "version": "3.12" }, "colab": { "name": "solving-motion-initial-conditions.ipynb", "provenance": [] }, "tirta": { "lesson": "https://tirta.co/a-byte-of-physics/solving-motion-initial-conditions", "source_sha256": "56b047cf15ff26b56a5fcef39ebe41479e6e03fc81b3c82189ce9c3ecf91bb47" } }, "nbformat": 4, "nbformat_minor": 5 }